| Sail
Area Math
by Jim Michalak
BACKGROUND...
If you look at the picture below of the sail rig of Mayfly12
you will see on the sail some (fuzzy) writing (that didn't scan
well) that says "55 square feet" to the left of a
small circle that represents the center of that area (honest).

Fig 1
The center of that area is often called a "centroid"
and you will see it is placed more or less directly above the
center of the leeboard's area. That is very important.
As you might imagine a shallow flat hull like this with a deep
narrow leeboard wants to pivot around that leeboard. If the
forces of the sail, which in a very general way can be centered
at the sail's centroid, push sideways forward of the leeboard,
the boat will tend to fall off away from the wind. You should
be able to hold the boat on course with the rudder but in that
case the rudder will have "lee helm" where you have
to use the rudder to push the stern of the boat downwind. The
load on the rudder will add to the load of the leeboard. Sort
of a "two wrongs make a right" situation and generally
very bad for performance and safety in that if you release the
tiller as you fall overboard the boat will bear off down wind
without you.
If the centroid is aft of the leeboard you will have "weather
helm", a much better situation. The rudder must be deflected
to push the stern towards the wind and the force on it is subtracted
from the load on the leeboard. Not only that, but when you release
the tiller as you fall overboard the boat should head up into
the wind and stall and wait for you if you are lucky. It's a
good deal but if you overdo it you can end up with too much
load on the rudder.
This balance problem is actually one of the few things about
sail rigs that is not arbitrary. The type of rig and its area
are pretty arbitrary depending on how fast you want to go, how
much you weigh, etc. But balance is quite important and is one
of the areas where backyard boaters get into trouble, sometimes
changing the boat or rig with no thought of balance. So before
you go doing that you should do a little homework. This essay
will tell you how to figure sail area and find the centroid.
One last item: the balance situation shown for Mayfly12 is
what I have found to be best for this type of boats. Boats with
large fin keels don't balance that way - usually the sail centroid
is well forward of the keel centroid. That distance is called
the "lead". That type of boat is not within my personal
experience and I'm not going to get into that. But you still
would have to figure the area and centroid.
THREE SIDED SAILS...

Fig 2
This one is really easy. The area is just the base time the
height divided by 2. Any side can be the base and the height
is aways at a right angle to the base.
So when you lay out the sail you draw it up on thin paper to
the same scale as your hull drawing with the leeboard (or daggerboard
or centerboard) lowered. Draw a line through the center of the
board straight up. Now we're going to locate the scale sail
on the boat such that it's centroid falls very close to that
line.
Here's how you find the centroid of a triangular sail.

Fig 3
Find the midpoint of each side and and draw a
line from that midpoint to the vertex opposite it. The three
lines will intersect at the centroid. Actually you only need
to find the intersection of two lines but the third line is
a good check.
That's it! Now you can take you scale sail drawing and slide
it around your hull drawing until the centroid is on that line
drawn up from the hull's board. Move it up and down and tilt
it until you like the way it looks. But don't cheat much forward
or aft of that line.
FOUR SIDED SAILS...
To find the area of a four sided sail you just divide it into
two triangles, find the area of each triangle as above, and
add the two together.

Fig 4
Now to find the centroid of the four sider. Start
by finding the centroids of the two triangles that make up the
four sided sail as shown above. Now draw a line from one triangle
centroid to the other. The centroid of the four sider is on
that line somewhere.

Fig 5
To find exactly where the centroid is on that
line, measure the length of that connecting line. You need not
use the same scale as is used on the drawing. I prefer to use
a millimeter scale for this measurement. Then get out the calculator
and work the formula shown in the Figure 4. Let's say for example
the length of the connecting line on the scale drawing measures
120 mm (that is measurement L). Let's say the example sail has
a lower triangle area of 50 square feet (that is A1). The upper
triangle is 35 square feet (that is A2). So the total sail area
is 50 + 35 = 85 square feet. The length L1, which will exactly
locate the sail's total centroid, is L1 = 120 x 35/85 = 49.4
mm. So you take that millimeter scale and measure up from A1
centroid on the connecting line 49.4 mm and make a tick mark
on the connecting line. That is the centroid of the total sail.
Another way to find the centroid, especially of a really odd
shaped sail, is to take the scale drawing of the sail and cut
it out. Then balance the cutout on a knife edge and mark the
balance line, rotate the cutout on the knife edge about 90 degrees
and rebalance and mark the new balance line. The centroid lies
at the intersection of the two line.
Another way is to dangle the cutout on a pin stuck through
a corner and into a wall marked with a vertical line that passes
through the pin point. Mark the line that passes through that
pivot corner and a vertical. Then rotate the cutout to hang
it from another corner, and mark a second line through the second
pivot corner and a vertical. The centroid lies at the intersection
of those two lines. Back at the missle factory the designers
had a favorite place, complete with pivot pin socket hole and
vertical line, to hang these cutouts and that place was known
as the "weighing wall". Meanwhile the super computer
cranked away next door but its answers weren't to be trusted
unless they agreed with the cutout hanging at the weighing wall.
RIGS WITH MANY SAILS...
Figure 5 shows the rig for Viola22. It has a main gaff sail
of 177 square feet, and a mizzen sail of 45square feet. Where
is the centroid of the assembly?

Fig 6
It's done exactly as with Figure 4. Draw a line
connecting the areas of the two sails. Measure the length of
the connecting line. Then run through the same equation as in
Figure 4. Nothing to it.
One thing I might point out about the Viola22
rig is that the total centroid falls near the aft edge of the
leeboard. By my experience the mizzen is not as efficient as
its area suggests so it needs to be a bit oversized by normal
rules, fudging the total centroid aft. I think in general the
aft sails operate in the scrambled flow of the forward sail,
causing loss of force back there.

Jim
has more information on his extensive website, like the essay
on tabernacles, or the one on jiffy-reefing systems. I encourage
you to visit the site at:
http://homepages.apci.net/~michalak/
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